retroleds wrote:...My original purpose in examining those traces was to determine if they could be bypassed with a resistor of correct resistance, to regain function...
With all we know by now, this should be possible!
To sum it up: they are simple resistors. No heat spreader, no temperature compensation, no heat compensator, no inductor, no capacitor, etc. Just simple resistors with ~90kOhms resistance.
However, you have to consider that if you "bypass" them with an SMD resistor, you will in fact connect the original and the bypass resistor in parallel, so the resulting resistance is NOT simply the value of the bypass resistor, but always less. And if the residue of the original resistor shows some awkward variable behaviour, the combination with a bypass resistor will also be variable, but to a lesser extent.
The formula is: R = 1 / ( (1/Ro) + (1/Rb) )
R=resulting resistance, Ro=actual resistance of original resistor, Rb = bypass resistor; all values in kOhm.
Or, to calculate the required bypass resistor: Rb = 1 / ( (1/R) - (1/Ro) ). With desired R=90k, this results in: Rb = 1 / ( 0.0111 - (1/Ro) ).
(You will find that if you insert Ro less than 90kOhm in the formula, the bypass resistor needs negative resistance - voilà, a negistor
)